2^(7-2x)=32

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Solution for 2^(7-2x)=32 equation: 



2^(7-2x)=32

We move all terms to the left:

2^(7-2x)-(32)=0

We add all the numbers together, and all the variables

2^(-2x+7)-32=0

We move all terms containing x to the left, all other terms to the right

2^(-2x+7)=32

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